Debugging 101: A SharePoint Developer's Guide to Learn and Prepare for interviews

Form MVC 3 or MVC 2 the objs passed in the form of json are automatically converted model format if the model of that type of object exists. Example Let say we have a model 'Customer' Public class Customer { public int CustomerID {get; set;} public string CustomerName {get; set;} public string CustomerAddress {get; set;} } Here we have a model 'Customer' with 3 attributes ID, Name, Address. Now we need to have a Get method and a post method public ActionResult Index() { return View(""); } [HttpPost] public ActionResult Index( Customer modelCustomer) { // Do your stuff here return View ("") } Here i have two different Function in the above code one is the httpGet method this is used to call the view where as the other is used to call the post method form the view may be using Submit or using ajax calls. here goes the code for ajax call @model iEnumerable @using (Html.BeginForm("Index", "Home" , FormMethod.Post , ...

There are two different ways of doing this . * Passing parent view that contains both the models which we want to pass in the view . * passing each model in a ViewBag we have two different models public class Customer { public int CustomerID {get; set;} public string CustomerName {get; set;} } public class Product { public int ProductId {get; set ;} public string ProductName{get; set ;} } 1. By passing a parent view Here we want to pass both the models in a single view , by default the razor engine only accepts single model per view. so we need to create a parent view that hold both the models. public class ParentView { public Customer customer{get; set;} public Product product{get ; set;} } then we can call the model in the view by using the following code in view page : @model iEmumerable <models.ParentView> ForEach(var v in ParentView) { < option > @v.customer.CustomerID < / option > < option > @v.customer.CustomerName <...